How do I get the repl url from python code?
Write this code to make webserver and get webserver url
Write this code
from flask import Flask
app = Flask('app')
@app.route('/')
def hello_world():
return 'Hello, World!'
app.run(host='0.0.0.0', port=8080)
Or the repl that you made and want get that repl url
It looks like this
https://replit.com/@arhanansari2009/NiftyBoilingMegabyte#main.py in your editor and others https://replit.com/@arhanansari2009/NiftyBoilingMegabyte?v=1
Hope it works
If it works mark it as Solution
Proper solution:
REPL_SLUG = os.getenv("REPL_SLUG")
REPL_OWNER = os.getenv("REPL_OWNER")
REPL_URL = f"https://{REPL_SLUG}.{REPL_OWNER}.repl.co"
Don’t write your code like this
Instead write this
```py
write you code here```
That won’t work lol. You have to it like this:
No? This:
```py
print(“hello world!”)
```
Becomes
print("hello world!")
Note: IIRC adding “py” there just tells the formatter what code it is so it doesn’t have to guess.
Wait…No to me or them?
I thought you were saying that doing ```py wouldn’t work, hang on.
Nah I meant doing
write you code here```
wouldn’t work.
Test```
Just checking
Hmm. What about
Test ```
Nope. Has to be on a new line.
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