Need immediate help can't find error in program

dict1 = eval (input (" enter first dictionary: "))
dict2 = eval(input ("enter second dictionary: “))
count = 0
for i in dict1:
for j in dict2 :
if i==j:
count +=1
if count == len (dict1) :
print (” when d1 is contained in d2 : ")
else:
print ("d1 not contained in d2 ")

Can you post the error?

enter first dictionary: int
enter second dictionary: bool
Traceback (most recent call last):
File “main.py”, line 4, in
for i in dict1:
TypeError: ‘type’ object is not iterable

the indentations are not a problem

I ran the code and didn’t get any error, is this correct:

dict1 = eval (input (" enter first dictionary: "))
dict2 = eval(input ("enter second dictionary: "))


count = 0
for i in dict1:
	for j in dict2:
		if i==j:
			count +=1
			
if count == len (dict1) :
	print (" when d1 is contained in d2 : ")
else:
	print ("d1 not contained in d2 ")
1 Like

it is correct, thank you must be some problem with the software I guess

the error still persists

thank you for your kind help

Hmm, I can’t replicate the error so I don’t know what your issue is. I can say that if you are trying to check if one dict is a subset of another, there is a much easier way to do it:

d1 = {"a" : 1, "b" : 2}
d2 = {"a" : 1, "b" : 2, "c" : 3}

if d1.items() <= d2.items():
	print(f"{d1} is a subset of {d2}")

Output:

{'a': 1, 'b': 2} is a subset of {'a': 1, 'b': 2, 'c': 3}

what input are you using?

1 Like

Agree - this is most likely the cause of the error rather than the code.

1 Like

This is the question
Program to check if a dictionary is contained in another or not.

I tried programming like:
dict1 = eval (input (" enter first dictionary: "))
dict2 = eval(input ("enter second dictionary: "))

count = 0
for i in dict1:
for j in dict2:
if i==j:
count +=1

if count == len (dict1) :
print (" when d1 is contained in d2 : ")
else:
print ("d1 not contained in d2 ")

As they said the code isn’t the problem, what are you giving the program as input?

ie: what are you entering when it asks enter first dictionary: and enter second dictionary

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