Another solution is to create a virtual keyboard, not as nice as the native iPhone keyboard but does the job
import tkinter as tk
def press(key):
if key == "Space":
key = " "
elif key == "Back":
current_text = name_entry.get()
name_entry.delete(0, tk.END)
name_entry.insert(0, current_text[:-1])
return
elif key == "Enter":
ask_name_and_greet()
return
current_text = name_entry.get()
name_entry.delete(0, tk.END)
name_entry.insert(0, current_text + key)
def ask_name_and_greet():
name = name_entry.get()
greeting_label.config(text=f"Hello, {name}!" if name else "No name entered.")
root = tk.Tk()
root.title("Greeting Application with Virtual Keyboard")
name_entry = tk.Entry(root, font=("Helvetica", 16))
name_entry.pack(pady=10)
greeting_label = tk.Label(root, text="Welcome!", font=("Helvetica", 16))
greeting_label.pack(pady=20)
keyboard_frame = tk.Frame(root)
keyboard_frame.pack(pady=10)
# Define keyboard layout
keys = [
['1', '2', '3', '4', '5', '6', '7', '8', '9', '0'],
['Q', 'W', 'E', 'R', 'T', 'Y', 'U', 'I', 'O', 'P'],
['A', 'S', 'D', 'F', 'G', 'H', 'J', 'K', 'L', 'Enter'],
['Z', 'X', 'C', 'V', 'B', 'N', 'M', ',', '.', 'Back'],
['Space'],
]
for row in keys:
frame = tk.Frame(keyboard_frame)
frame.pack(side=tk.TOP)
for k in row:
button = tk.Button(frame, text=k, command=lambda k=k: press(k), padx=3, pady=3)
button.pack(side=tk.LEFT)
root.mainloop()