help with 
I’ve got the logic and the flowchart but I think I mess with the syntax.
Write a program that always asks the user to enter a number. When the user enters the negative number -1, the program should stop requesting the user to enter a number. The program must then calculate the average of the numbers entered excluding the -1.
Make use of the while loop repetition structure to implement the program.
Hello, could you please share (at least) your logic, and possibly the flowchart as well? That way we have a starting point to work from.
Hi…
well the logic is…
print(input("enter a number: "))
if the number is different then -1 should go back and ask again to enter another number
so that would be the … while loop
while x != -1
???
if the input is -1 then will break the loop and print the average
which would be
x = x/len(x)
???/
print(input("number: "))
count=0
sum=0
while (count != (-1)):
input (“number”)
print(‘average of list’‘is’,(sum/len(count)))
I’m not very good on explaining myself so, please be patient
Formatting this to python real quick…
x = input("enter a number: ")
# if the number is different then -1 should go back and ask again to enter another number
# so that would be the … while loop
while x != -1
# ???
# if the input is -1 then will break the loop and print the average
# which would be
x = x/len(x) # Exp
# ???/
x = input("number: ") # Exp and two lines below
count=0
sum=0
while (count != -1): # Infinite loop
x = input("number")
print('average of list","is",(sum/len(count)))
If possible please explain the lines that I added # Exp to.
count=0
sum=0
a= input("number: ")
while a != -1:
print(a)
count += 1
else:
print(‘average of list’‘is’,(sum/len(count)))
this is where I am, sorry im not very helpfull
i tried to start from scratch a few times but I always end with the same code and I don’t understand why. At this point I’m not sure if I need to declare those variables or no.
I found different examples to calculate the average of a list of numbers but none for the average of a list of introduced numbers
count=0
sum=0
a= input("number: ")
while (a != (-1)):
print(a)
else:
print(‘average of list’‘is’,(sum/len(count)))
this is the first example I checked and tried to start from
a=[19, 25, 74, 38, 99, 39, 18, 83, 10, 50]
count=0
sum=0
while (count<len(a)):
sum=sum+a[count]
count=count+1
print(‘average of list’,a,‘is’,(sum/len(a)))
Please format your code like this:
Get this result:
print("Hello world")
Using this method:
```python
print("Hello world")
```
this is giving me the average of the list of numbers in “a”
and it says, while count is less then the numbers on the list add 1 on count so it will keep going for 10 times and then will calculate the average.
a=[19, 25, 74, 38, 99, 39, 18, 83, 10, 50]
count=0
sum=0
while (count<len(a)):
```count=count+1
print('average of list',a,'is',(sum/len(a)))
what i dont understand is If I declare a variable like
x = print(input("enter a number: "))
will x be a string of caracters or numbersTaking a guess at what you want here…
while x != -1
x = int(input("Input the first number: "))
count=0
total=0
numberList = [x]
while (x != -1): # Infinite loop
x = int(input("Input the next number (-1 to exit): "))
total += x
numberList.append(x)
print("Average of the list","is",(total/len(numberList)))
I’m fairly certain the bulk of that code should work (Not sure if “len()” is right though, I never remember)
Edit: made some tweaks so we shouldn’t be overwriting any keywords.
sorry very confuse now
Im in England, is 18:35 and I think I will sleep on it and come back tomorrow
ill see if I can catch up with you tomorrow with a bit more of brain fresh
Hello,
well, I’ve got some progress.
Now the program is asking to enter numbers until you type ‘-1’.
once typed ‘-1’ the while loop breaks and print "the average is: "
none of the average functions is working for me.
i tried mean(), (sum(x) / len(x)), and some others but I cant make it work.
any hints about the average calculation?
numbers = str(-1)
print("enter a numbers different then: ", numbers)
request = input("or -1 to calculate the average: ")
# average = numbers / numbers
while (numbers != request):
request = input("enter another number: ")
average = int(request)
average = request/len(request)
print("the average is: ", average)
Maybe this?:
sum = 0
count = 0
# Ask the user to enter a number
num = float(input("Enter a number (-1 to stop): "))
# Keep looping until the user enters -1
while num != -1:
# Add the number to the sum and increment the count
sum += num
count += 1
# Ask the user to enter another number
num = float(input("Enter a number (-1 to stop): "))
# Calculate the average (if there were numbers entered)
if count > 0:
average = sum / count
print("The average of the", count, "numbers entered is", average)
else:
print("No numbers were entered.")
the following basically gets as many valid numbers as possible until they input ‘stop’ (allows the person to input negative numbers). Code is super ugly and I normally wouldn’t write something like this but I wrote this completely here so 
def one_num():
x = input("please input a number: ")
while not (x.isdigit() or (x[0] == '-' and x[1:].isdigit() or x == 'stop'):
x = input("please input a number: ")
if (x != 'stop'):
return int(x)
else:
return None
amt = 0
current = 0
while True:
x = one_num()
if (x is None): break
amt += 1
current += x
if (amt > 0):
print(current / amt)
else:
print("You need to input things -_-")
I always think I know Python so well until I see a code that you make lol.
I know, that happened to me when I was learning Japanese
you see, languages are all the same.
morphology, semantic, and syntaxis
Joining the frail with another silly version …
sum = 0
nums = 0
while True:
try:
new_number = int(input("type new number or -1 to stop: "))
except:
print("invalid number")
continue
if new_number == -1:
break
sum += new_number
nums += 1
if nums == 0:
print("no number given.")
else:
print("average is", sum/nums)
oh nah, there’s no way! You are a much better programmer than me
lol yeah was gonna use try/catch but slow XD
you need to use the try/catch … something of an habit i hope gets picked up … otherwise move to go and manage the errors (which is much much better)